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gpu: nvgpu: Update channel on semaphore release
When using semaphore based channel synchronization, a semaphore release may mean that a job has completed. Call gk20a_channel_update from gk20a_channel_semaphore_wakeup to check if there are memory refs to release or sync timelines to signal. Bug 1450122 Change-Id: Ib829c895dab05676c35f974d3f1c3d88c047c9b9 Signed-off-by: Lauri Peltonen <lpeltonen@nvidia.com> Reviewed-on: http://git-master/r/394576 Reviewed-by: Automatic_Commit_Validation_User GVS: Gerrit_Virtual_Submit Reviewed-by: Terje Bergstrom <tbergstrom@nvidia.com>
This commit is contained in:
committed by
Dan Willemsen
parent
e204224b26
commit
dbde063bf6
@@ -1994,8 +1994,10 @@ void gk20a_channel_semaphore_wakeup(struct gk20a *g)
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for (chid = 0; chid < f->num_channels; chid++) {
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for (chid = 0; chid < f->num_channels; chid++) {
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struct channel_gk20a *c = g->fifo.channel+chid;
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struct channel_gk20a *c = g->fifo.channel+chid;
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if (c->in_use)
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if (c->in_use) {
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wake_up_interruptible_all(&c->semaphore_wq);
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wake_up_interruptible_all(&c->semaphore_wq);
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gk20a_channel_update(c, 0);
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}
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}
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}
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}
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}
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