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The Linux timer code prints an error message containing the caller when a timeout happens. The caller is formatted as a function name instead of a pointer, so don't print 0x in front of it. Bug 1799159 Change-Id: I4f86d885aba78ca20ba025a91c8c940d3c927d58 Signed-off-by: Konsta Holtta <kholtta@nvidia.com> Reviewed-on: http://git-master/r/1315749 Reviewed-by: svccoveritychecker <svccoveritychecker@nvidia.com> GVS: Gerrit_Virtual_Submit Reviewed-by: Terje Bergstrom <tbergstrom@nvidia.com>